Questions About Electric Power Transmission

Transmission of electrical power is commonly performed on high voltage, either using the HVAC (high voltage alternating current) and HVDC (high voltage direct current). the former uses an alternating current and this is contained in our country. The second course uses direct current. in this post, I will not touch such a question: Which is better, HVAC or HVDC? My problem is something more fundamental, namely concerning the reasons why the transmission done at a high voltage (even extra high) . it was clear from some college (khususnya high voltage engineering) that the transmission of electrical power carried on the high voltage to reduce losses associated with the transmission line impedance. but ... .Please refer to here to find out more about the various voltage values commonly used in transmission lines and its classification.
if I may use my own words, when the transmit power, (in fact) we send both voltages and currents. Say we are given the freedom to choose who we keep the nominal voltage on transmission lines. if the voltage is made low, to a certain power, current that flows will be large, and vice versa if the voltage is made high. both options look the same if no impedance of the transmission line itself. in fact not the case, the transmission line impedance is always there and will never be ignored. then what's the problem? 

 Remember P = VI 

Of course we can not change the heart as good as the tension mounted in the customer for electrical equipment (load) is only designed to work on the voltage (and frequency) specific. These constraints can be overcome by using a transformer, and I think do not need further explanation about it.
presence of the transmission line impedance cause munculnyalosses , that magnitude is I ^ 2 * Z. seen here would reduce the current importance that are channeled through the transmission network in order to minimize losses. it just means the transmission of electrical power should be done at high voltage ^. " Who Will Pay for losses? " said Mr. T. Hary, my Lecturer at high voltage engineering class. ho3x ... it's all about money ...:) There are other alternatives, we can minimize the impedance channel. however, it was not enough to minimize losses. in ways that were used (to minimize the impedance channel) indicates that the cost to do so is relatively large.
unanswered questions ...
answered? Eits wait a minute ...
way of thinking on so vividly and convincingly give reasons why the transmission done at high voltage. however, for some reason one time, I remembered a similar case, but not the same, which may (should) be given on the course Fundamentals of electrical engineering (especially circuit theory). I mean the maximum power transfer theorem. This theorem says that the power (active) output (ie used the load) can be maximized if the load resistance is made equal to the resistance network (say a cable) or the source.
roughly, be seen that the maximum power transfer theorem "is not ignored at all" on the transmission line. come confused like me then? quiet ... 2x. confused confused now better than when pendadaran ...:). although the goal to be achieved in both cases (ie the transmission channel and maximum power transfer theorem) is the same, (ie) so that power is channeled to the load is as large as possible and also other equations such as the resistance (or impedance) channel, but if explored further, both cases turned out completely different. 

on transmission lines, power generated from the source is fixed, while the cases in which the maximum power transfer theorem applies is the system with the source voltage (or current source) are fixed, thus the source of power that can be supplied in the second case may vary. that fundamental differences. in the second case, if using a voltage source, which supplied power source is V ^ 2 / (R + RL), while the power used by load is [V / (R + RL)] ^ 2 * RL. V (voltage source) and R (resistance line + source) is a fixed quantity, so that power (especially those used on the load) is a function of load resistance (RL). analog thing happens if you use current source. in the first case, the amount of power supplied by the source equipment, such as P, while the load power used is P-(V1-V2) ^ 2 / R. V1 is the voltage on the secondary side travo step-ups, while V2 is the voltage on the primary side travo step-down, so that unused power at the load is a function of the voltage transmission line.